ggplot2 |
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3.3.3 |
This material is intended to supplement pages 87 to 105 of Cleveland’s book.
Bivariate data are datasets that store two variables measured from a same observation (e.g. wind speed and temperature at a single location). This differs from univariate data where only one variable is measured for each observation (e.g. temperature at a single location).
A scatter plot is a popular visualization tool used to compare values between two variables. Sometimes one variable is deemed dependent on another variable; the latter being the independent variable. Cleveland refers to the former as the response and the latter as the factor (this is not to be confused with the factor data type used in R as a grouping variable). The dependent variable is usually plotted on the y-axis and the independent variable is usually plotted on the x-axis. Other times, one does not seek a dependent-independent relationship between variables but is simply interested in studying the relationship between them.
A scatter plot can be generated using the base plotting environment as follows:
<- read.csv("http://mgimond.github.io/ES218/Data/ganglion.csv")
df
plot(cp.ratio ~ area, dat = df)
Or, using ggplot2
, as follows:
library(ggplot2)
ggplot(df, aes(x = area, y = cp.ratio)) + geom_point()
The data represent the ratio between the ganglion cell density of a cat’s central retina to that of its peripheral density (variable cp.ratio
) and the cat’s retina surface area (area
) during its early development (ranging from 35 to 62 days of gestation).
Scatter plots are a good first start in visualizing the data, but this is sometimes not enough. Our eyes need “guidance” to help perceive patterns. Another visual aid involves fitting the data with a line.
A straight line is the simplest fit one can make to bivariate data. A popular method for fitting a straight line is the least-squares method. We’ll use R’s lm()
function which provides us with a slope and intercept for the best fit line.
In the base plotting environment, we can do the following:
<- lm(cp.ratio ~ area, dat = df)
M plot(cp.ratio ~ area, dat = df)
abline(M, col = "red")
In the ggplot2
plotting environment, we can make use of the stat_smooth
function to generate the regression line.
library(ggplot2)
ggplot(df, aes(x = area, y = cp.ratio)) + geom_point() +
stat_smooth(method ="lm", se = FALSE)
The se = FALSE
option prevents R from drawing a confidence envelope around the regression line.
The straight line is a first order polynomial with two parameters, \(a\) and \(b\), that define an equation that best describes the relationship between the two variables:
\[ CP_{Ratio} = a + b (Area) \]
where \(a\) and \(b\) can be extracted from the regression model object M
as follows:
coef(M)
(Intercept) area
0.01399056 0.10733436
Thus \(a\) = 0.014 and \(b\) = 0.11.
A second order polynomial is a three parameter function (\(a\), \(b\) and \(c\)) whose equation \(y = a + bx + cx^2\) defines the curve that best fits the data. We define such a relationship in R using the formula cp.ratio ~ area + I(area^2)
. The identity function I()
preserves the arithmetic interpretation of area^2
as part of the model. Our new lm
expression and resulting coefficients follow:
<- lm(cp.ratio ~ area + I(area^2) , dat = df)
M2 coef(M2)
(Intercept) area I(area^2)
2.8684792029 -0.0118691702 0.0008393243
The quadratic fit is thus,
\[ y = 2.87 - 0.012 x + 0.000839 x^2 \]
We cannot use abline
to plot the predicted 2nd order polynomial curve since abline
only draws straight lines. We will need to construct the line manually using the predict
and lines
functions.
plot(cp.ratio ~ area, dat=df)
<- data.frame( area = seq(min(df$area), max(df$area), length.out = 50) )
x.pred <- predict(M2, x.pred)
y.pred lines(x.pred$area, y.pred, col = "red")
To do this in ggplot2
simply pass the formula as an argument to stat_smooth
:
ggplot(df, aes(x = area, y = cp.ratio)) + geom_point() +
stat_smooth(method = "lm", se = FALSE, formula = y ~ x + I(x^2) )
A more flexible curve fitting option is the loess curve (short for local regression; also known as the local weighted regression). Unlike the parametric approach to fitting a curve, the loess does not impose a structure on the data. The loess curve fits small segments of a regression lines across the range of x-values, then links the mid-points of these regression lines to generate the smooth curve. The range of x-values that contribute to each localized regression lines is defined by the \(\alpha\) parameter which usually ranges from 0.2 to 1. The larger the \(\alpha\) value, the smoother the curve. The other parameter that defines a loess curve is \(\lambda\): it defines the polynomial order of the localized regression line. This is usually set to 1 (though ggplot2
’s implementation of the loess defaults to a 2nd order polynomial).
Behind the scenes, each point (xi,yi) that defines the loess curve is constructed as follows:
gaussian
weight being the most common. Another weighting strategy we will also explore later in this course is the symmetric
weight.The above steps are repeated for as many xi values practically possible. Note that when xi approaches an x limit, the subset of points becomes skewed to one side of xi. For example, when estimating x10, the seven closest points to the right of x10 are selected.
In the following example, just under 30 loess points are computed at equal intervals. This defines the shape of the loess.
It’s more conventional to plot the line segments than it is to plot the points.
The loess fit can be computed using the loess()
function. It takes as arguments span
(\(\alpha\)), and degree
(\(\lambda\)).
# Fit loess function
<- loess(cp.ratio ~ area, df, span = 0.5, degree = 1)
lo
# Predict loess values for a range of x-values
<- seq(min(df$area), max(df$area), length.out = 50)
lo.x <- predict(lo, lo.x) lo.y
The predicted loess curve can be added using the lines
function.
plot(cp.ratio ~ area, dat = df)
lines(lo.x, lo.y, col = "red")
In ggplot2
simply pass the method="loess"
parameter to the stat_smooth
function.
ggplot(df, aes(x = area, y = cp.ratio)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 0.5)
However, ggplot
(up to version 3.3) defaults to a second degree loess (i.e. the small regression line elements that define the loess are defined by a 2nd order polynomial and not a 1st order polynomial). If a first order polynomial (degree=1
) is desired, you need to include an argument list in the form of method.args=list(degree=1)
to the stat_smooth
function.
ggplot(df, aes(x = area, y = cp.ratio)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 0.5,
method.args = list(degree = 1) )
Fitting the data with a line is just the first step in EDA. Your next step should be to explore the residuals. The residuals are the distances (along the y-axis) between the observed points and the fitted line. The closer the points to the line (i.e. the smaller the residuals) the better the fit.
The residuals can be computed using the residuals()
function. It takes as argument the model object. For example, to extract the residuals from the linear model M
computed earlier type,
residuals(M)
1 2 3 4 5 6 7 8 9 10
1.3596154 1.3146525 0.5267426 -0.1133131 -0.1421694 0.3998247 -1.2188692 -2.0509148 -1.8622085 -0.1704418
11 12 13 14
-0.5788861 0.4484394 -1.0727624 3.1602905
We’ll create a residual dependence plot to plot the residuals as a function of the x-values. We’ll do this using ggplot
so that we can also fit a loess curve to help discern any pattern in the residuals (the ggplot
function makes it easier to add a loess fit than the traditional plotting environment).
$residuals <- residuals(M)
dfggplot(df, aes(x = area, y = residuals)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 1,
method.args = list(degree = 1) )
We are interested in identifying any pattern in the residuals. If the model does a good job in fitting the data, the points should be uniformly distributed across the plot and the loess fit should approximate a horizontal line. With the linear model M
, we observe a convex pattern in the residuals suggesting that the linear model is not a good fit. We say that the residuals show dependence on the x values.
Next, we’ll look at the residuals from the second order polynomial model M2
.
$residuals2 <- residuals(M2)
dfggplot(df, aes(x = area, y = residuals2)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 1,
method.args = list(degree = 1) )
There is no indication of dependency between the residual and the area
values. The second order polynomial is an improvement over the first order polynomial. Let’s look at the loess model.
$residuals3 <- residuals(lo)
dfggplot(df, aes(x = area, y = residuals3)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 1,
method.args = list(degree = 1) )
The loess model also seems to do a good job in smoothing out any overall pattern in the data.
You may ask “if the loess model does such a good job in fitting the data, why bother with polynomial fits?” If you are seeking to generate a predictive model that explains the relationship between the y and x variables, then a mathematically tractable model (like a polynomial model) should be sought. If the interest is simply in identifying a pattern in the data, then a loess fit is a good choice.
Next we will look for homogeneity in the residuals.
The M2
and lo
models do a good job in eliminating any dependence between residual and x-value. Next, we will check that the residuals do not show a dependence with fitted y-values. This is analogous to univariate analysis where we checked if residuals increased or decreased with increasing medians across factors. Here we will compare residuals to the fitted cp.ratio
values (think of the fitted line as representing a level across different segments along the x-axis). We’ll generate a spread-level plot of model M2
’s residuals (note that in the realm of regression analysis, such plot is often referred to as a scale-location plot). We’ll also add a loess curve to help visualize any patterns in the plot (this reproduces fig 3.14 in Cleveland’s book).
<- data.frame( std.res = sqrt(abs(residuals(M2))),
sl2 fit = predict(M2))
ggplot(sl2, aes(x = fit, y =std.res)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 1,
method.args = list(degree = 1) )
The function predict()
extracts the y-values from the fitted model M2
and is plotted along the x-axis. It’s clear from this plot that the residuals are not homogeneous; they increase as a function of increasing fitted CP ratio. The “bend” observed in the loess curve is most likely due to a single point at the far (right) end of the fitted range. Given that we have a small batch of numbers, a loess can be easily influenced by an outlier. We may want to increase the span.
ggplot(sl2, aes(x = fit, y = std.res)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 1.5,
method.args = list(degree = 1) )
The point’s influence is reduced enough to convince us that the observed monotonic increase is real (Note that we would observe this monotone spread with our loess model as well). At this point, we should look into re-expressing the data.
If you are interested in conducting a hypothesis test (i.e. addressing the question “is the slope significantly different from 0”) you will likely want to check the residuals for normality since this is an assumption made when computing a confidence interval and a p-value. We’ll make use of geom_qq
and geom_qq_line
to compare the residuals to a normal distribution.
ggplot(df, aes(sample = residuals2)) + geom_qq(distribution = qnorm) +
geom_qq_line(distribution = qnorm, col = "blue")
Here, the residuals seem to stray a little from a normal distribution.
The monotone spread can be problematic if we are to characterize the spread of cp.ratio
as being the same across all values of area
. To remedy this, we can re-express the cp.ratio
values. Ratios are good candidates for log transformation. We will therefore fit a new linear model to the data after transforming the y-value.
<- data.frame( area = df$area, cp.ratio.log = log(df$cp.ratio))
df.log <- lm(cp.ratio.log ~ area, dat = df.log) M3
Next, let’s plot the transformed data and add the fitted line.
ggplot(df.log, aes(x = area, y = cp.ratio.log)) + geom_point() +
geom_smooth(method = "lm", se = FALSE)
At first glance, the log transformation seems to have done a good job at straightening the batch of values. Next, let’s look at the residual dependence plot.
$residuals <- residuals(M3)
df.logggplot(df.log, aes(x = area, y = residuals)) + geom_point() +
stat_smooth(method = "loess", se = FALSE, span = 1,
method.args = list(degree = 1) )
Logging the y values has eliminated the residual’s dependence on area
. Next, let’s assess homogeneity in the residuals using the s-l plot.
<- data.frame( std.res = sqrt(abs(residuals(M3))),
sl3 fit = predict(M3))
ggplot(sl3, aes(x = fit, y = std.res)) + geom_point() +
stat_smooth(method ="loess", se = FALSE, span = 1,
method.args=list(degree = 1) )
We do not observe a systematic increase in spread, the log transformation seems to have removed the monotone spread.
Finally, we’ll check for normality of the residuals.
ggplot(df.log, aes(sample = residuals)) + geom_qq(distribution = qnorm) +
geom_qq_line(distribution = qnorm, col = "blue")
An added benefit of re-expressing the data seems to be a slight improvement in the normality of the residuals.